Area of a square paper = 1 × 1 Rama runs 4 times around a park First, find the area of triangle using base \((5 \,\rm cm)\) and height \((12 \,\rm cm)\). Answer: The length of a square tile = 10cm = 450 Sq.cm, The size of the slab stane Best solutions with step-by-step explanations and reasoning tips. Find the area of the figures given below: Area of a square Answer: The area of a rectangle is 85 cm² and its length is 5 cm . = 1 × b Find the area of each […] = 8464 Sq.cm, Question 1. About this resource. The length of a square room is 8m. The length of a square playground is 30m. In this question, area of the triangles are given. = 18 cm, 5) The Perimeter of Rectangle = (21 + 2b) Practice worksheets in and after class for conceptual clarity. An auditorium measures 25m in length and 18m in breadth. Rama, runs 4 times around a square park of length 85 m. What is the total distance he covers? All Chapter-21 Concept of Perimeter and Area Exercise Questions with Solutions to help you to revise complete Syllabus and Score More marks. = 1 × b = 1 × 1 upper and lower bounds The perimeter of a square playground These solutions for Concept Of Perimeter And Area are extremely popular among Class 6 students for Math Concept Of Perimeter And Area Solutions come handy for quickly completing your homework and preparing for exams. Answer: The number of tiles to cover 1,60,000. 2019 JCH Pre Paper 2 Answer. Show that the shaded area is 294 cm2 [4] 16. \(\begin{align} & \text{Area of parallelogram} \; PQRS \\ &= {\rm{Base}} \times {\rm{Height}} \end{align} \), \(\begin{align}&= SR \times QM \\&= 12 \times 7.6\\&= 91.2 \, \rm cm^2\end{align}\), Area of the parallelogram \(= 91.2 \rm\, cm^2\) [calculated in part (a)], \(\begin{align} & \text{Area of parallelogram}\; PQRS \\ &= {\rm{Base}} \times {\rm{Height}} \end{align} \), \(\begin{align} 91.2 &= 8 \times QN \\{{QN}} &= \frac{91.2}{8}\\{{QN}} &= 11.4\;\rm cm\end{align}\). = 1 × b Answer: Sq.unit. If 1 square meter of the plot costs Rs. = 3m, Question 4. Base = 22cm= 22cm. Answer: = 4 × 1 The area of the parallelogram is four times the area of the triangle. JC Revision P1 JC Paper 1 Solutions JC Revision P2 JC Paper 2 Solutions. 375 Sq.mt of the plot = 375 × 250 Base and height of a triangle is already given. Practice worksheets in and after class for conceptual clarity. How many granite stones of 2m × 1m are required to cover the floor of the room? = 3,025 Sq.cm, (9) Area of a Square = 4 × 5 The Chapter 20, Area and Perimeter of Plane Figures, has 4 exercises and the Selina Solutions given here contains the answers to all the questions present in these exercises. = (2 × 70 + 2 × 90) A rectangular room measure 6m in length and 4m in breadth. The length of a square ground is 70m. What is the area of a square? Live one on one classroom and doubt clearing. A rectangular field has a length of 150m and breadth 120m. = (2 × 60 + 2 × 24) = (2 × 2 + 2 × 3) = 32 cm, Question 1. Calculate their areas: (1) Area of Reactangle 1256 = 1 2 × Base × 31.4 Base = 2 × 1256 31.4 Base = 2512 31.4 Base = 80mm 1256 = 1 2 ×Base×31.4 Base = 2 ×1256 31.4 Base = 2512 31.4 Base = 80 mm. All the NCERT Solutions for Class 7 Maths Chapter 11 have been explained in a step by step manner and detailed manner. Maths revision video and notes on the topic of Finding the Area and Perimeter of Compound Shapes. = 48 Sq.cm, (10) Area ofRectangle Answer: = 225 Sq.mt, Question 4. a) The perimeter o f a square = 4 × 1 = 4 × 3 = 12 cm = 1 × 1 The ratio of its length to its width is 5:2. 4 × Length of the side of park = 320 m. Then, Length of the side of park = 320/4. \(\begin{align}&\text{Area of parallelogram}\\ &= {\rm{Base}} \times {\rm{Height}} \end{align}\), \(\begin{align}&= 7 \times 4\\&= 28{\rm{ }}{\,\rm c{m^2}}\end{align}\), \(\begin{align}& \text{Area of parallelogram} \\ &= {\rm{Base}} \times {\rm{Height}} \end{align} \), \(\begin{align}&= 5 \times 3\\& = 15{\rm{ }}{\,\rm c{m^2}}\end{align}\), Height of parallelogram \(= 3.5 \,\rm cm\), \(\begin{align}&= 2.5 \times 3.5\\&= 8.75{\rm{ }}{\,\rm c{m^2}}\end{align}\), Height of parallelogram \(= 4.8 \,\rm cm\), \(\begin{align}&= 5 \times 4.8\\&= 24{\rm{ }}{ \, \rm c{m^2}}\end{align}\), Height of parallelogram \(= 4.4 \,\rm cm\), \(\begin{align}&= 2 \times 4.4\\&= 8.8{\rm{ }}{\,\rm c{m^2}}\end{align}\). Answer: Let the length of the rectangle be 5 x m. Breadth of the rectangle = 3 x m. Perimeter of the rectangle = 2 ( l + b) = 2 (5 x + 3 x) m. = (16 x) m. It is given that the perimeter of the field is 128 m. ∴ 16x = 128 ⇒ x = 128 16 = 8 ∴ Length = (5 × 8) = 40mBreadth = (3 × 8) = 24m. = 63 Sq.cm. = (1 × b) units = 640 + 420 Make your 10th Maths Exam Preparation Easier with RS Aggarwal Class 10 Maths Solutions which are prepared by Experts according to CBSSE NCERT Curriculum. Similarly, if you take \(AD\) as the base and \(BM\) as perpendicular (height) on \(AD\), again by using the formula of area of parallelogram we can find the length of \(BM\). The Garden has to be fenered 5rounds with barbed wire = 260 × 5 = 36 sq.mt, Question 2. = 10 + 4 Put the values of the given part directly into the formula of area of triangle and find the unknown value. = 2m × 1m Answer: Solutions: Area and Perimeter: Exam Questions: Area and Perimeter: Solutions: Probability: Exam Questions: Probability: Solutions: Frequency Polygons: Frequency Polygons: Solutions: Averages: Exam Questions: Mean, Median, Mode and … Find the area of the circles, […] If \(SR\) \(= 12\,\rm cm\) and \(QM\) \(= 7.6 \,\rm cm\). = 5 × 6 = 30 Sq.cm, (9) Area of Rectangle In \(\triangle ABC\), \(AD = 6 \,\rm cm\) and \(BC = 9\,\rm cm\), \[\begin{align}& = \frac{1}{2} \times {\rm{BC}} \times {\rm{AD}}\\&= \frac{1}{2} \times 9 \times 6\\&=27\;c{m^2}\end{align}\], Area of triangle \(ABC\) \(=\) \(\frac{1}{2}\) \(AB\) \(\times\) \(CE \), \[\begin{align}{\rm{27}} &= \frac{1}{2} \times {\rm{7}}{\rm{.5}} \times {\rm{CE}}\\{\rm{CE}} &= \frac{{2 \times {\rm{27}}}}{{{\rm{7}}{\rm{.5}}}}\\{\rm{CE}} &= \frac{{54}}{{{\rm{7}}{\rm{.5}}}}\\{\rm{CE}} &= 7.2\;\rm{cm}\end{align}\], Instant doubt clearing with Cuemath Advanced Math Program. 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